| Author |
Message |
    
Ron
| | Posted on Monday, June 17, 2002 - 03:07 am: | 
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Can anyone explain to be what amount of driveshaft out of phase = correction for what deviation of driveshaft angles from ideal?
Maybe a formula or something?
I "heard" something and what to try it but I want to have a working knowledge of this concept first.
Thanks
Ron |
hendrik
| | Posted on Monday, June 17, 2002 - 06:56 am: |
|
Sorry, I cant give you the desired information.
But I had my front driveshaft (RangeRover 3.9) in a local specialist shop. I forgot how much exactly it is twisted=out of phase. Must be between 41-44 degrees. They said that doing this to driveshafts would be quite common (Mercedes G-Wagon?), but they have not seen it to that degrees.
Therefore I`d think that as found in our Rovers it (out phase) is perfect for the standard driveshaft angles in standard and lifted vehicles upto 2". But cannot be pushed much further.
But there certainly is a formular for computing how much out phase would be necessary. One will have to ask someone who is in the business.
regards,
Hendrik |
RonLF
| | Posted on Monday, June 17, 2002 - 10:40 am: |
|
From what I have read, the front shaft is out of phase 40 degrees. This is not needed with a CV driveshaft. So if you are making a new shaft use a CV and the phase will be in-line(zero degees). If you are asking about a stock driveshaft then 40 degees is the factory set-up. |
Ron
| | Posted on Monday, June 17, 2002 - 10:47 pm: |
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anyone bump it up some more? Thats kinda what I was thinking about. Also I am doing an axle swap on Noah (the series) and thought about adjusting it there to compensate for the 1/2in less offset.
And I was wondering how much was possible to put it out of phase?
Ron |
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