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Bill K (Bill_K)
Posted on Monday, September 30, 2002 - 08:00 am:   Edit Post Delete Post Print Post

Just changed out the tensioner bearing as per the TIP thread and while the belt was off, I noticed my AC compressor and power steering pulleys were a bit looses (i could jiggle them a little bit front to back). Can I replace the bearings on those pulleys the same way as in the tensioner? Thanks all.
 

Paul T. Schram (Paulschram)
Posted on Monday, September 30, 2002 - 09:00 am:   Edit Post Delete Post Print Post

Don't know about the air compressor, but you are opening a nasty can of worms when you open the power steering pump. Not real hard to put back together, but you might end up with a handful of bearings and an o-ring in your hand!

Finding the bearings can be something of a challenge also as most Rover shops say they can't be serviced.

The power steering pump is a really simple device and the play you encountered might not be out of bounds.

Paul
 

Bill K (Bill_K)
Posted on Monday, September 30, 2002 - 09:55 am:   Edit Post Delete Post Print Post

For the AC compressor, can I just unbolt the central bolt and remove the pulley/clutch? Could it be that simple? Is there someplace that illustrates the parts of a compressor? Ah gots ta know!
 

Paul T. Schram (Paulschram)
Posted on Monday, September 30, 2002 - 10:26 am:   Edit Post Delete Post Print Post

Try your local air conditioning shop?

I remember back a while, somebody talking about how the bearings in the A/C pump were very common and inexpensive.

We have to get lucky once in awhile, eh?

Paul
 

Bill K (Bill_K)
Posted on Monday, September 30, 2002 - 10:31 am:   Edit Post Delete Post Print Post

Here's a quote I got off the D-90 website.

" Idler Pulley (A/C) 62302-2RSJ [bl-15] Made by Consolidated Bearings, and possibly others.
Size should be 42mm OD, 15mm ID, and 17mm wide/thick [approx]
Press the old bearing out and press the new one in, then re-stake at the factory stake points to keep the bearing tight in the pulley. The shoulder bolt is a slip fit in the ID of the bearing. "

Is it this simple?

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